Re: [MW:28903] Interpretation: IX-10-23 Subject: QW-433 and QW-452.1(b) Date Issued: March 14, 2011 File: 10-1918

depositing 0.100 in. of E6010 and the balance  - 2t only as per 452.1 b , means 0.100 2t = 0.200 not 0.864 

regard

rajesh 

On Wed, Jan 9, 2019 at 7:09 PM muneebslsa@gmail.com <muneebslsa@gmail.com> wrote:

Greetings,

I have clarifications with below interpretaion for question 1 and agree with 2 and 3, does anyone has any observations on Q1?

Interpretation: IX-10-23 Subject: QW-433 and QW-452.1(b) Date Issued: March 14, 2011 File: 10-1918 

Background: A welder tests on an NPS 6 Sch. 80 (0.432 in. wall) coupon, depositing 0.100 in. of E6010 and the balance of 0.332 in. using E7018. Question (1): Using E6010, is the welder qualified to deposit 0.864 in. maximum of weld metal? Reply (1): Yes. Question (2): Using E7018, is the welder qualified to deposit 0.664 in. maximum of weld metal? Reply (2): Yes. Question (3): Is the welder qualified to deposit 0.864 in. of weld metal using E6010 plus 0.664 in. of E7018 weld metal deposit thickness for a total of 1.528 in. in the same groove? Reply (3): No. See QW-452.1(b).

Thanks.

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