Dear Gents,
-- Would some one explain me the below interpretation:
Background: A welder tests on a NPS 6 Sch80 .432 wall coupon, depositing .100 in of 6010 and the balance of .332 using 7018.
Question 1, Using 6010, is the welder qualified to deposit .864 in Maximum of weld metal? 864 = 2T
Reply was: yes
Question 2. Using 7018 is the welder qualified to deposit .644 in weld metal. 644 = 2t
Reply was Yes.
Question 3. Is the welder qualified to deposit .864 in. of weld metal using 6010 plus .664 in. of 7018 weld metal for a deposit of 1.528 in the same groove.
Reply was: no See QW 452.1 (b)
Question 1, Using 6010, is the welder qualified to deposit .864 in Maximum of weld metal? 864 = 2T
Reply was: yes
Question 2. Using 7018 is the welder qualified to deposit .644 in weld metal. 644 = 2t
Reply was Yes.
Question 3. Is the welder qualified to deposit .864 in. of weld metal using 6010 plus .664 in. of 7018 weld metal for a deposit of 1.528 in the same groove.
Reply was: no See QW 452.1 (b)
why a welder gets 2T coupon thickness limit (for weld metal deposited) when he only deposited the root and hot-pass using 6010. Then same welder gets only 2t weld metal thickness for the 7018?
I will be thankful for a piece of advice on this issue.
Regards,
Venkkatesh Gopalakrishna/
https://materials-welding.blogspot.com/
https://www.linkedin.com/groups/122787
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