Re: [MW:30213] weld thickness

Please Refer QW-433 ASME Sec iX

1.If a welder qualified for F4 with backing can weld F3 with backing as per QW-433

Welder is already qualified for F3 without backing 0.200 inch max (2×0.100 inch) and One more 0.664 inch with F3 he can weld total 0.864 inch.

2. For thickness of weld metal qualified refer QW-452.1(b)

For example welder deposited F4 0.332 inch thickness weld metal deposited.

Maximum weld metal deposited will ne 2×0.332= 0.664.

Mohammed Tajuddin

On Fri, 30 Aug 2019, 9:53 pm Raghul, <raghul351991@gmail.com> wrote:

Background: A welder tests on an NPS 6 Sch. 80 (0.432 in. wall) coupon, depositing 0.100 in. of E6010 and the balance of 0.332 in. using E7018.

Question (1): Using E6010, is the welder qualified to deposit 0.864 in. maximum of weld metal?

Reply (1): Yes.

Question (2): Using E7018, is the welder qualified to deposit 0.664 in. maximum of weld metal?

Reply (2): Yes.

Question (3): Is the welder qualified to deposit 0.864 in. of weld metal using E6010 plus 0.664 in. of E7018 weld metal deposit thickness for a total of 1.528 in. in the same groove?

Reply (3): No

Above clauses are get from ASME ix interpretation.

Please explain  Using E6010, how the welder qualified to deposit 0.864 in. maximum of weld metal???????

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